H12-831_V1.0試験無料問題集「Huawei HCIP-Datacom-Advanced Routing & Switching Technology V1.0 認定」
On the OSPF network shown in the figure, drag the values on the left to the correct positions so that:
* Traffic from PC1 to PC2 follows the path:PC1 -> R1 -> R3 -> R2 -> PC2
* Traffic from PC2 to PC1 follows the path:PC2 -> R2 -> R1 -> PC1
Which of the following OSPF cost values should be assigned to Cost-A, Cost-B, and Cost-C to achieve this routing behavior?

* Traffic from PC1 to PC2 follows the path:PC1 -> R1 -> R3 -> R2 -> PC2
* Traffic from PC2 to PC1 follows the path:PC2 -> R2 -> R1 -> PC1
Which of the following OSPF cost values should be assigned to Cost-A, Cost-B, and Cost-C to achieve this routing behavior?

正解:

Explanation:
* A = 50
* B = 10
* C = 20
Comprehensive and Detailed In-Depth Explanation:
Understanding OSPF Path Selection and Cost Calculation:
* OSPF selects the shortest path (lowest cost) to the destination.
* The OSPF cost is determined by the cumulative sum of interface costs along a path.
* By assigning specific costs to A, B, and C, we can influence OSPF's path selection to meet the desired routing behavior.
Step-by-Step Analysis of Required Traffic Flow:
1. Traffic from PC1 to PC2 must take the route:
PC1 -> R1 -> R3 -> R2 -> PC2
* To force traffic through R3, the cost of the direct link R1 -> R2 (Cost-A) must be higher than the alternative path via R3.
* We assign Cost-A = 50 (high cost) to discourage direct routing from R1 -> R2.
* The cost of R1 -> R3 (Cost-C) should be lower, so we assign Cost-C = 20.
* The cost of R3 -> R2 (default Cost-20) remains unchanged.
* Total cost via R3: 20 (R1->R3) + 20 (R3->R2) = 40, which is less than the direct link of 50, so OSPF prefers this path.
# Traffic follows: PC1 -> R1 -> R3 -> R2 -> PC2
2. Traffic from PC2 to PC1 must take the route:
PC2 -> R2 -> R1 -> PC1
* We need to make R2 -> R1 (Cost-B) the best (lowest cost) route for return traffic.
* Assign Cost-B = 10 (low cost).
* This ensures that R2 prefers the direct path R2 -> R1 instead of R2 -> R3 -> R1 (which costs
20+20=40).
# Traffic follows: PC2 -> R2 -> R1 -> PC1
Final Cost Assignments for Correct Routing Behavior:
Cost
Assigned Value
Reason
Cost-A (R1 -> R2)
50
High to discourage direct R1->R2 routing
Cost-B (R2 -> R1)
10
Low to ensure PC2->PC1 prefers direct R2->R1
Cost-C (R1 -> R3)
20
Medium to encourage R1->R3->R2 path
Key Takeaways:
* Higher OSPF cost discourages path selection.
* Lower OSPF cost encourages path selection.
* By manipulating OSPF cost values, we achieve asymmetric routing between PC1 and PC2.
* This aligns with OSPF path selection principles covered in HCIP-Datacom certification.
HCIP-Datacom-Advanced Routing & Switching Technology References:
* Huawei HCIP-Datacom Official Certification Guide, Chapter on OSPF Cost Calculation and Path Selection.
* Huawei Enterprise Networking Training Materials, OSPF Path Optimization Techniques.
* Huawei Datacom Configuration Guide, OSPF Cost and Traffic Engineering.
On the OSPF network shown in the figure, R1 and R2 use OSPF to communicate with each other through Loopback0. In addition:
* MPLS LDP is enabled on R1 and R2.
* The LDP transport address is the IP address of Loopback0.
* A network engineer finds that an LDP session cannot be established between R1 and R2 and runs diagnostic commands (shown in the figure) to locate the fault.
Given this, which of the following are possible causes of the fault?

Options:
* MPLS LDP is enabled on R1 and R2.
* The LDP transport address is the IP address of Loopback0.
* A network engineer finds that an LDP session cannot be established between R1 and R2 and runs diagnostic commands (shown in the figure) to locate the fault.
Given this, which of the following are possible causes of the fault?

Options:
正解:B,C
解答を投票する
解説: (GoShiken メンバーにのみ表示されます)
On the OSPF network shown in the figure, area 1 is a common area, area 2 is a stub area, and area 3 is an NSSA. R5 imports an external route 10.0.5.5/32. Given this, which of the following routers does not have the route 10.0.5.5/32 in its routing table?


正解:A
解答を投票する
解説: (GoShiken メンバーにのみ表示されます)
On the network shown in the figure, IS-IS runs on R1, R2, R4, and R5, and the area ID is 49.0001. IS-IS runs on R3 and R6, and the area ID is 49.0002. In AS 65000, R1, R3, R4, and R6 each establish iBGP peer relationships with R2 and R5. R2 and R5 are RRs (Route Reflectors), and R1, R4, R3, and R6 are clients. The iBGP peer relationships are established using Loopback0 on each router, and the router ID is 10.0.0.X/32, where X is the number of the router. R1 and R4 import the external route 192.168.1.0/24 to BGP through the import-route command, and R3 and R6 import the external route 192.168.2.0/24 to BGP through the import- route command. Which of the following statements are true?


正解:B
解答を投票する
解説: (GoShiken メンバーにのみ表示されます)
On the network shown in the figure, IS-IS runs on R1, R2, R4, and R5, and the area ID is 49.0001. IS-IS runs on R3 and R6, and the area ID is 49.0002. In AS 65000, R1, R3, R4, and R6 each establish iBGP peer relationships with R2 and R5. R2 and R5 are RRs (Route Reflectors), and R1, R4, R3, and R6 are clients. The iBGP peer relationships are established using Loopback0 on each router, and the router ID is 10.0.0.X/32, where X is the number of the router. R1 and R4 import the external route 192.168.1.0/24 to BGP through the import-route command, and R3 and R6 import the external route 192.168.2.0/24 to BGP through the import- route command. Which of the following statements are true?


正解:B,C
解答を投票する
解説: (GoShiken メンバーにのみ表示されます)